Tuesday, 7 February 2017

Approximation Problems For SBI PO Pre Exam 2017

     





What approximate value should come in place of question mark in the following equations.


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1. 816.23/34.98 × 24.999 = ?

1.560
2.540
3.520
4.580
5.600

2.(4722+3272+5324)/(491+769+132)=?

1.40
2.10
3.15
4.25
5.20

3.22 1/3 % of 435.1 -  11/7 % of 1734.68 = ?

1.59
2.62
3.50
4.69
5.78

4.(1681)^1/2 + (4094)^1/3 = ?

1.57
2.75
3.78
4.67
5.76

5.(803.63)² = ?

1.506000
2.787800
3.646400
4.767600
5.566000

6.(1.2)² / 1.3333  = (1.1)^? / (1.22)³

1.8
2.6
3.7
4.5
5.3

7. 2809/27.86 × 6.26 - 125.88 - 246.18 = ?

1.245
2.266
3.254
4.238
5.272

8.(13.67)² - (4.77)²+ (8.26)³ - (5.23)³ = ?

1.636
2.600
3.520
4.624
5.612

9.21% of 234.20 + 54% of 150 - 3.76% of 102.05 = ?

1.129
2.126
3.147
4.136
5.167

10.(1218)^2 / 18 = ? × 1224

1.90
2.67
3.70
4.60
5.78








Solutions and Answers :
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1.4

==> (816/35)×25 = 23×25 = 575

Nearest value in options is 580

2.2

==> 13316/1392 = 13400/1400 = 9.5

Nearest value in options is 10

3.4

==> 97-27 = 70

Nearest value in options is 69

4.1

==> 41 + 16 = 57

5.3

==> (804)^2 = 646414

Nearest value in options is 646400

6.4

==> (1.1)^2 / (1.1)³= (1.1)^? / (1.21)³
==>(1/(1.1)) = (1.1)^? / (1.1)^6
==> ? = 5

7.3

==> 2809 / 28 × 6.25 - 126 - 246 = 625-372 = 253
Nearest value in options 254

8.2

==> 188-23+572-144=760-167=593

Nearest value in options is 600

9.2

==> 49+81-4 = 126

10.2

==> (1218)^2 / 18 = ? ×1224 = 67.33 = 67


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For Assam GK Click On Below Link
http://assamdarpan.blogspot.in/2017/02/miscellaneous-questions.html?m=1



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http://ssksuraj.blogspot.in/?m=1

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