IBPS PO 2017 DAY 7

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Study the following information carefully and answer the given questions.

There are seven national parks namely Jim Corbett, Ranthambore, Kaziranga, Periyar, Bandipur, Manas and Satpura located in different cities such as Chennai, Mumbai, Kochi, Hyderabad, Bangalore, Patna & Kolkata, not necessarily in the same order. Different animals such as, Lion, Tiger, Elephant and Deer were presented in the park. Depends on the length of the Parks it was listed from 1 to 7 positions, from top to bottom. The following information is known about them.
·        Not more than 3 Parks has same animals.
·        There's only one park has Deer which belongs to Bangalore and listed in bottom 3 positions and is not Kaziranga Park
·        The one belongs to Chennai listed just ahead of Ranthambore Park, which does not belong to Bangalore.
·        The park in which Tiger presented is listed 1st.
·        The Parks which listed in 3rd and 4th have same animals and it is not Lion.
·        The park located in Mumbai listed in last and park located in Patna listed as 4th and none of them are has Tiger.
·        Manas Park have Lion animal and is not in bottom 3.
·        Periyar Park belongs to Hyderabad and Satpura Park belongs to Chennai, both are not having lion animal and in the list there are two Parks between them.
·        The Parks from Kolkata and Mumbai are having same animals.
·        Bandipur Park not located in Kochi, Mumbai or Bangalore.








Study the following information carefully and answer the given questions.

Six friends - Harish, Mohan, Suresh, Vikram, Ram, and Gopal went to six different cities namely Mumbai, Bangalore, Hyderabad, Delhi, Chennai and Patna (not necessarily in the same order) to attend different probationary officers exam. They exams are IBPS PO, SBI PO, BOB PO, Syndicate Bank PO, Indian Bank PO and Dena Bank PO. They attend exams from Monday to Saturday (not necessarily in the same order).
·        Harish attends exam in Delhi and he wrote either IBPS PO or Dena Bank PO.
·        Ram did not wrote Dena Bank PO exam
·        Suresh attends exam on Tuesday and he is not wrote IBPS PO or BOB PO exam.
·        The person who wrote the Syndicate Bank PO exam wrote on Saturday and neither in Mumbai nor in Bangalore.
·        Gopal wrote the SBI PO exam in Patna but not on Wednesday.
·        Ram attends the exam at Hyderabad and wrote the exam one day before Gopal
·        On first day of the week, Mohan attends the exam in Bangalore.
·        The person who attends the exam on Thursday is not wrote BOB PO or IBPS PO exam.
·        The person who attends the exam on Thursday is not Gopal.




Directions (Q. 1-5): In each of the questions below there are given four conclusions followed by five statements numbered I, II, III, IV & IV. You have to take the given statements to be true even if they seem to be at variance with commonly known facts. Read all the statements and then decide which of the given statement logically follows from the given conclusion disregarding commonly known facts.

1). Conclusions:
Some cups are balls
Some pins are car is a possibility
Some rings are balls
Some balls are pins is a possibility
a)  Statements:
Some balls are cars
Some cars are rings
All rings are cups
Some cups are pins
b)  Statements:
Some cars are balls
All cars are rings
All rings are cups
Some cups are pins
c)  Statements:
All balls are cars
Some cars are rings
All rings are cups
Some cups are pins
d)  Statements:
Some balls are cars
All cars are rings
All rings are cups
No cup is a pin
e)  Statements:
All balls are cars
All cars are rings
All rings are cups
No cup is a pin
a)   Only I follows  
b)   Only II follows
c)   Only II & III follows
d)   Only IV follows
e)   Only V follows

2). Conclusions:
Some pencils are tables
All chairs are boxes
Some boxes are desk
All desks are pencils
a)  Statements:
Some desks are chairs
All chairs are tables
All tables are boxes
Some boxes are pencils
b)   Statements:
Some desks are chairs
No chair is table
All tables are boxes
All boxes are pencils
c)  Statements:
All desks are chairs
All chairs are tables
All tables are boxes
All boxes are pencils
d)  Statements:
All desks are chairs
All chairs are tables
No table is box
Some boxes are pencils
e)  Statements:
All desks are chairs
All chairs are tables
All tables are boxes
No box is pencil
a)   Only I follows  
b)   Only I & II follows
c)   Only III follows
d)   Only IV follows
e)   Only V follows

3). Conclusions:
Some rivers are not roads
Some jungles may be roads
Some cars are roads
Some rivers are trees
a)  Statements:
All roads are cars
No car is tree
All trees are jungles
All jungles are rivers
b)  Statements:
All roads are cars
Some cars are trees
All trees are jungles
Some jungles are not rivers
c)  Statements:
All roads are cars
No car is tree
Some trees are not jungles
All jungles are rivers
d)  Statements:
Some roads are cars
No car is tree
Some trees are not jungles
Some jungles are rivers
e)  Statements:
All roads are cars
No car is tree
Some trees are jungles
All jungles are rivers
a)   Only I follows  
b)   Only II follows
c)   Only II & III follows
d)   Only IV follows
e)   Only V follows


4). Conclusions:
Some pens are pins is a possibility
Some pencils are pads
Some papers are pads is a possibility
Some papers are pens
a)  Statements:
Some pens are papers
Some pencils are papers
Some pads are pencils
Some pins are pads
b)  Statements:
Some pens are papers
Some pencils are papers
No pad is a pencil
Some pins are pads
c)  Statements:
All pens are papers
Some pencils are papers
All pads are pencils
Some pins are pads
d)  Statements:
Some pens are papers
All papers are pencils
Some pads are not pencils
Some pins are pads
e)  Statements:
No pen is a paper
All papers are pencils
Some pads are pencil
Some pins are pads
a)   Only I follows  
b)   Only II follows
c)   Only II & III follows
d)   Only I & III follows
e)   Only IV & V follows

5). Conclusions:
All papers are cups
Some plates are cup is a possibility
Some cups are jugs
Some bottles are papers
a)  Statements:
All papers are bottles
Some bottles are cups
Some cups are jugs
Some jugs are plates
b)  Statements:
All papers are bottles
All bottles are cups
Some cups are jugs
Some jugs are plates
c)  Statements:
Some papers are bottles
Some bottles are cups
Some cups are jugs
Some jugs are plates
d)  Statements:
All papers are bottles
All bottles are cups
Some cups are not jugs
Some jugs are plates
e)  Statements:
Some papers are bottles
All bottles are cups
Some cups are jugs
Some jugs are plates
a)   Only I follows  
b)   Only II follows
c)   Only II & IV follows
d)   Only I & III follows
e)   Only V follows

PROFIT AND LOSS: PART-2

Type 6:

1). An article was purchased for Rs. 78,350/-. Its price was marked up by 30%. It was sold at a discount of 20% on the marked up price. What was the profit percent on the cost price?

Solution:

Cost Price = Rs.78350

Marked Price = 78350 x 130/100 = Rs.101855

Selling Price = 101855 x 80/100 = Rs.81484

Profit = 81484 – 78350 = 3134

Therefore Profit% = 3134/78350 x 100 = 4%

Type 7:

2). A shopkeeper purchases 12 balloons for Rs.10 and sells them at 10 balloons for Rs.12.Thus, he earns a profit of

Solution:

Number of Balloons purchased and sold be = LCM (12,10) = 60

CP = 60/12 x 10 = 50; SP = 60/10 x 12 = 72

Profit = (72 – 50)/50 x 100 = 22/50 x 100 = 44%

Type 8:

3). The cost price of an article is Rs. 800. After allowing a discount of 10%, a gain of 12.5% was made. Then the marked price of the article is

Solution:

CP = Rs 800

Gain% = 12.5%

SP = 800 + 12.5% of 800 = 800 + 25/200 x 800 = 800 + 100 = Rs 900

MP = SP + Discount

MP = 900 + 10% of MP

MP – MP/10 = 900

9MP/10 = 900

MP = (900 x 10)/9 = Rs 1000

Type 9:

4). If the selling price of an article is doubled, then its loss per cent is converted into equal profit per cent. The loss per cent on the article is

Solution:

Let CP = C, SP = S, Loss% = x %

=> x = (C – S)/C x 100 --------------(1)

When SP is doubled, loss% becomes profit%.

x = (2S – C)/C x 100 --------------(2)

From eqns (1) and (2)

2S – C = C – S

3S = 2C => S = 2/3 C

Substituting b = 2/3 a in eqn (1)

x = (C – 2/3 C)/C x 100= (C/3)/C x 100  = 100/3 = 33 1/3%

Type 10:

5). A man bought an article listed at Rs. 1500 with a discount of 20% offered on the list price. What additional discount must be offered to man to bring the net price to Rs. 1,104?

Solution:

SP of the article = MP – Discount = 1500 – 20% of 1500 = 1500 – 300 = Rs 1200

Therefore, additional discount = (1200 – 1104)/1200 x 100 = (96/1200) x 100 = 8%

Exercise Questions:

1). Giri purchased 100 shirts at Rs. 450 per piece. While selling he offered 10%discount on the labeled price and earned a profit of 20%. What was the labeled price of each shirt?

a)   Rs. 540

b)   Rs. 650

c)   Rs. 590

d)   Rs. 600

e)   None of these

2). If the cost price of 15 Pencils is equal to the selling price of 12 pencils, find gain percent.

a)   20

b)   25

c)   18

d)   21

e)   None of these

3). A dealer purchased a printing machine for Rs. 7660. He allows a discount of 12% on its marked price and still gains 10%. Find the marked price of the machine. 

a)   9575

b)   8765

c)   10985

d)   8995

e)   None of these

4). A fruit seller buys oranges at 2 for a rupee and sells them at 5 for three rupees. His gain percent is

a)   10%

b)   15%

c)   20%

d)   25%

e)   30%

5). The labeled price of a Juicer is Rs.620. If it is sold at 15% discount and the dealers earn a 20% profit, what is the cost price?

a)   Rs.439.16

b)   Rs.423.16

c)   Rs.412.16        

d)   Rs.436.11

e)   None of these

6). A person sold an toy for Rs. 136 and got 15% loss, had he sold it for Rs. N, he would have got a profit of 15%. Which one of the following is correct?

a)   190 < N < 200

b)   180 < N < 190

c)   170 < N < 180

d)   160 < N < 170

e)   None of these

7). A person bought an old Bike at Rs.7200 and spent 15% of it on repairing. If he wants to make a profit of Rs.648 then what percentage should be added to purchase price?

a)   15%       

b)   20%

c)   24%

d)   25%

e)   None of these

8). A shopkeeper gave an additional 40% discount on the reduced price after giving 25% standard concession on that item, if a person bought that item for Rs.1260, what is the original price of the item?

a)   Rs.2400

b)   Rs.2800

c)   Rs.3200

d)   Rs.2000

e)   None of these

9). 20 mangoes were bought for a rupee. Approximately how many mangoes must be sold for a rupee to gain a profit of 30%?

a)   12

b)   10

c)   15

d)   20

e)   25

10). A seller wants to earn 12% profit on an item after giving 20% discount to the customer. By what percentage should he increase his marked price to arrive at the label price?

a)   24%

b)   32%

c)   42%

d)   16%

e)   None of these

_____________________________________________

Answers with Explanation: Reasoning

Directions (Q. 1-5): Syllogism

1). B)

2). C)

3). A)

4). D)

5). D)

Answers with Explanation: MATH

1). Answer: d)

Let the labeled price of each shirt be Rs. x.

According to the question,

90% of x = 120 × 450 / 100

90 / 100 × x = 120 × 450 / 100

x = 120 × 450 / 90

x = Rs. 600

2). Answer: b)

Gain percent = (15 – 12) / 12 × 100 = 25%

3). Answer: a)

Cost price of the machine = Rs. 7660, Gain% = 10%.
Therefore, selling price = [{(100 + gain%)/100} × CP]
                                     = Rs. [{(100 + 10)/100} × 7660]
                                     = Rs. [(110/100) × 7660]
                                     = Rs. 8426.
Let the marked price be Rs. x.
Then, the discount = 12% of x
                               = {x × (12/100)}
                               = 3x/25
Therefore, SP = (Marked Price) - (discount)
                       = (x - 3x/25)
                       = 22x/25.
But, the SP = Rs. 8426.
Therefore, 22x/25 = 8426
⇒ x = (8426 × 25/22)
⇒ x = 9575.
Hence, the marked price of the Printing machine is Rs. 9575. 

4). Answer: c)

The cost price of 1 lemon =Rs.0 .50
Selling price of 1 lemon = Rs.0.60;  

Therefore,  profit = Rs.0.10
:.  Gain per cent = 0.10 × 100/0.50 = 20%.

5). Answer: a)

The selling price = Rs.620 – 15% of 620 = 620 – 93 = Rs.527

Rs.527 is 120% of the cost price;

Therefore, cost price = 527 × 100/120 = Rs.439.16.

6). Answer: b)

Cost price = (selling price x 100)/(100 - loss%)
= (136 x 100)/(100 - 15)
= (136 x 100)/85
= Rs. 160
Selling price (N) = 160 x (100 + 15)/100 = (160 x 115)/100
= Rs. 184
∴ Option (b) is correct because [180 < N < 190].

7). Answer: c)

CP = Rs.7200
CP + repair cost + profit expected = Rs.7200 + 1080 +648 = Rs.8928.
The amount to be added to CP = Rs.8928 – Rs.7200 = Rs.1728
The percentage of amount to be added to CP = 1728 x 100/7200 = 24%

8). Answer: b)

Let the original price be ‘x’

The price after 1st concession of 25% = x – 25x/100 = x – x/4 = 3x/4

The Price after additional discount 40% = 3x/4 – 3x/4 X 40/100 = 30x – 12x/40

= 9x/20, i.e. 9x/20 = Rs.1260,

:. x = 1260 x 20 /9 = Rs.2800.

9). Answer: c)

Given 20 mangoes cost 100 paisa.

:. 1 mango’s cost = 5 paisa.

For a getting a profit of 30% , the SP per mango should be equal to 6.5 paise.

:. For 1 Rupee, the No. of mangoes to be sold = 100/6.5

= 15 nos. approximately.

10). Answer: e)

Let x = marked price and the CP be Rs.100.

Initial SP = Rs.112.

To give 20% discount = x – 20x/100 = Rs.112.

= x – x/5 = Rs.112,  4x = 112 x 5

x = Rs.140.

Here marked profit = Rs.40.

Percent profit 40%