Friday, 14 July 2017

IBPS PO 2017 DAY 10

   




Directions (Q. 1-5): In each question two equations numbered I and II are given. You have to solve both the equations and mark the answer
a)   If x > y
b)   If x ≥ y
c)   If x < y
d)   If x ≤ y
e)   If x = y or no relation can be established between x and y.

1). I. 4x² – 15x + 14 = 0
II. 6y² – 10y + 4 = 0

2). I. 3x² + 10x + 3 = 0
II. 2y² + 15y + 27 = 0

3). I. 7x² + 12x + 5 = 0
II. 3y² + 7y + 2 = 0

4). I. 16x² – 14x + 3 = 0
II. 6y² – 19y + 15 = 0

5). I. x² + 11x + 18 = 0

II. y² - √81 = 0

Directions (Q. 6-10): In these questions, two equations numbered I and II are given. You have to solve both the equations and mark the appropriate option. Give answer
a)   If x > y
b)   If x ≥ y
c)   If x < y
d)   If x ≤ y
e)   If x = y or relationship between x and y can’t be established

6). I. 32491/2 x - √625 = 4079
II. 57761/2 - √324 = 4162

7). I. 3x – 2y = 37
II. 5x – 3y = 59

8). I. 9x² + 4x – 28 = 0
II. 2y² – 17y + 36 = 0

9). I. √169 x + 561 = 678
II. √324 y + 678 = 822

10). I. 7x² + 19x – 36 = 0
II. 2y² – 21y – 98 = 0





Study the following information carefully and answer the given questions.


Ten persons Shami, Kushak, Nanda, Pranav, Akil, Dileep, Jayanth, Ganapati, Rohan and Vendan are sitting in two rows with five persons in each row. The persons in row one are facing south and the persons in row two are facing north. Each person in row one faces a person from the other row. All of them have a watch of different companies, viz Maxima, Sonata, Matrix, Fossil, Fastrack, Casio, Timex, Citizen, Titan and Espoir, but not necessarily in the same order.
·        The persons who like Fastrack and Casio sit opposite each other.
·        Dileep sits opposite to Shami, who likes Maxima.
·        The one who likes Sonata sits opposite the one who likes Citizen.
·        Vendan is not facing north but sits third to the left of Jayanth, who likes Sonata.
·        There is only one person between Kushak and Nanda.
·        Akil sits at one of the ends of the row and likes Casio.
·        The one who likes Citizen is on the immediate right of Pranav, who does not like Espoir. 
·        The persons who like Matrix and Fossil respectively are not facing north.
·        Nanda likes Timex. The one who likes Fossil sits opposite the one who is second to the right of Kushak.
·        Rohan does not like Espoir. Akil sits opposite the one who sits second to the left of the one who likes Matrix.




Study the following information carefully and answer the given questions.



Ten Friends are sitting in two parallel rows of six seats each. One seat is vacant in each row. Bhavya, Janvi, Hemanika, Preeti and Dharini are sitting in row-1 facing south. Veni, Radha, Charmy, Nisha and Usha are facing north. Each likes a different brand of Soaps i.e. Hamam, Dove, Lux, Liril, Vivel, Pears, Nivea, Mysore Sandal, Medimix and Margo. Nisha sits third to the right of Charmy and likes Liril. Only two people sit between Radha and the vacant seat. Radha does not like Vivel or Lux Soap. Dharini is not an immediate neighbour of Hemanika. Janvi likes Margo. The one who likes Lux Soap faces the one who likes Mysore Sandal. The one who likes Lux sits opposite to the one who sits third right of the person who sits opposite to Nisha. Hemanika is not an immediate neighbour of Preeti. Usha, who likes neither Vivel nor Pears, does not face the vacant seat. Neither Nisha nor Charmy sits at any of the extreme ends of the row. Preeti faces Charmy. Vacant seats are not opposite to each other. Two seats are there between Hemanika and Janvi, who sits third right of the one who likes Nivea. The one who likes Medimix Soap faces the one who likes Liril. The friends who like the Hamam and Mysore Sandal are adjacent to each other. Vacant seat of row – 1 is not an immediate neighbour of Preeti. Radha sits at one of the extreme ends of the row. Charmy does not like Hamam and Mysore Sandal. Vacant seat of row-1 does not face Nisha who doesn’t sit at any of the extreme ends of the row.





Study the following information carefully and answer the given questions.
A number arrangement machine arranges two digit numbers in typical manner. The first step has been obtained by multiplying the digits in input.Multiplication has not been done in any other steps. They are obtained by applying certain logic. Each step is a resultant of previous step.

1.If each middle digit of all the three numbers in the step I are halved and then added, then what will be the final sum?


4
6.5
3.5
7.5
None of these

2.If the final output is subtracted from ‘5’, then what will be the resultant value?


-2.8
-3.2
2.8
3.2
None of these
3.Which of the following combination represent the first digit of the third number and second digit of the first number in step I of the given input?


(5,2)
(8,3)
(3,8)
(2,5)
(2,4)
4. Which of the following represent the difference between the third digit of the third number and second digit of the first number in step I?


4
5
6
-4
None of these

5.What is the multiplication of three numbers obtained in step II?


100
120
240
220
None of these








 ___________Solution with Explanation_________

1). I. 4x2 – 15x + 14 = 0
x = (-8/7), (-7/4)
x = 2, 1.75
II. 6y2 – 10y + 4 = 0
y = (-6/6), (-4/6)
y = 1, 2/3
Hence, x > y
Answer: a)

2). I. 3x2 + 10x + 3 = 0
x = (9/3), (1/3)
x = -3, -1/3
II. 2y2 + 15y + 27 = 0
y = (9/2), (6/2)
y = -4.5, -3
Hence, x ≥ y
Answer: b)

3). I. 7x2 + 12x + 5 = 0
x = (7/7), (5/7)
x = -1, -5/7
II. 3y2 + 7y + 2 = 0
y = (6/3), (1/3)
y = -2, -1/3
Thus relationship can’t be established.
Answer: e)

4). I. 16x2 – 14x + 3 = 0
x = (-8/16), (-6/16)
x = 1/2, 3/8
 II. 6y2 – 19y + 15 = 0
y = (-10/9), (-9/6)
y = 5/3, 3/2
Hence x < y.
Answer: c)

5). I. x2 + 11x + 18 = 0
x = (9/1), (2/1)
x = -9, -2
II. y2 - √81 = 0
y2  = √81
y2 = 9
y = ±3
Hence, no relation can be established.
Answer: e)

6). I. 32491/2 x - √625 = 4079
or, 57x = 4079 + 25 = 4104
x = 4104/57 = 72
II. 57761/2 - √324 = 4162
Or, 76y = 4162 +18 = 4180
y = 4180/76= 55
Hence x > y
Answer: a)

7). 3x – 2y = 37     …(i)
5x – 3y = 59           …(ii)
Equation (i) × 3 – (ii) × 2
(9x -6y = 111) + (10x – 6y = 118)
x = 7
Putting the value of x in eqn (i) we get
21 – 2y = 37
-2y = 36
y = (-16/2) = -8
Hence x > y
Answer: a)

8). I. 9x2 + 4x – 28 = 0
x = (18/9), (-14/9)
x = -2, 14/9
II. 2y2 – 17y + 36 = 0
Y = (-9/2), (-8/2)
Y = 4.5, 4
Hence x < y
Answer: c)

9). I. √169 x + 561 = 678
13x = 678 – 561 = 117
x = 117/13 = 9
II. √324 y + 678 = 822
18y = 822 – 678 = 144
x = 144/8
Hence x > y
Answer: a)

10). I. 7x2 + 19x – 36 = 0
x = (28/7), (-9/7)
x = -4, 9/7
II. 2y2 – 21y – 98 = 0
y = (-28/2), (7/2)
y = 14, -3.5
Hence relationship can’t be established.

Answer: e)










No comments:

GK For APDCL EXAM

Assam State GK for any Assam Govt. Exam PREP BY: OFFICERS' ACADMEY 1. National Game held in Assam – 2007 2. Guawahati tea auct...