Directions (Q. 1-10): Two equations (I) and (II) are given in each question. On the basis of these
equations you have to decide the relation between ‘x’ and ‘y’ and give answer.
(1) if x > y
(2) if x < y
(3) if x ≥ y
(4) if x ≤ y
(5) if x = y or no relation can be established between ‘x’ and ‘y’.
1) x² – 6√3x - 48 =0
y² - √2y - 24 = 0
2) x² + 5√3x - 42 = 0
y² - 8√2y + 30 = 0
3) x² - √2x - 24 = 0
y² - 8√3y + 45 = 0
4) 5x² + 4√10x + 8 = 0
4√3y² + 5y - 2√3 = 0
5) 2x² - ( 4+√13)x + 2√13 = 0
10y² - ( 18+5√13)y +9√13 = 0
6) x² + ( √7 - 4)x - 2√28 = 0
√3y² - ( 6-√21)y - 6√7 = 0
7) x² -x - √2x + √2 = 0
y² - 3y + 2 = 0
8) x² - 2x - √5x + 2√5 = 0
y² - √3y - √2y + 6 = 0
9) x² - 7√3x + 36 = 0
y² - 12√2y + 70 = 0
10) x² - 7√7x + 84 = 0
y² - 5√5y + 30 = 0
••••••••••••••••••••••••••••••••••••••••••••••••••••••••••••••••
Answer :-
1) 5
2) 2
3) 5
4) 5
5) 3
6) 5
7) 5
8) 1
9) 5
10) 1
1 comment:
1) x² – 6√3x - 48 =0
y² - √2y - 24 = 0. Expen plz
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