IBPS PO 2017 DAY 11

What will come in place of question mark(?) in the following number series?
1). 7  20  46  98  202   ?
a)   310
b)   410
c)   320
d)   330
e)   420

2). 210  209  217  190  254  ?
a)   129
b)   149
c)   249
d)   327
e)   159

3). 27  38  71  126  203   ?
a)   212
b)   202
c)   312
d)   301
e)   302

4). 435  354  282  219  165   ?
a)   103
b)   130
c)   112
d)   120
e)   None of these

5). 4  200  369  513  634   ?
a)   755
b)   734
c)   715
d)   788
e)   None of these

Directions (Q. 6-10): In each of following number series only one number is wrong. Find out that wrong number.
 6). 11  12  28  93  310  1965
a)   12
b)   93
c)   1965
d)   310
e)   28

7). 3  20  87  392  2025  12246
a)   12246
b)   87
c)   392
d)   20
e)   2025

8).12  6.8  7.5  12.75  27.5  71.25
a)   27.5
b)   7.5
c)   12.75
d)   71.25
e)   6.8

9). 5  33  225  1345  6724  26881
a)   225
b)   6724
c)   26881
d)   33
e)   225

10). 225  256  289  344  361  400
a)   225
b)   361
c)   344
d)   256
e)   400








Study the following information and answer the questions.
There are nine persons Prem, Vinoth, Harish, Ramesh, Satish, Atreya, Mohan, Gowtham and Yadav stay on a nine floors building, but not necessarily in the same order. Only one person stays on each floor. All of them clear either SBI PO or IBPS PO examination, Each of them presently working as a clerk in different banks i.e. Andra Bank, Bank of India, Canara Bank, Indian Bank, Syndicate Bank, Punjab National Bank, UCO Bank, Vijaya Bank and IDBI Bank, but not necessarily in the same order. Only five of them clear IBPS PO exam. The ground floor is numbered 1 and the topmost floor is numbered 9. There are two floors between the persons who working in a Punjab National Bank cleared SBI PO exam and who working in Vijaya Bank cleared IBPS PO exam. Harish working in Canara Bank cleared SBI PO exam. Atreya does not working in IDBI Bank but he cleared SBI PO exam. Prem stays on even numbered floor below the even numbered floor on which Gowtham stays. The one who working in Syndicate Bank cleared IBPS PO exam stays on the fourth floor. Ramesh stays on the second floor and working in Indian Bank cleared IBPS PO exam. The one who working in Bank of India cleared IBPS PO exam stays on the topmost floor. Prem does not working in UCO Bank cleared IBPS PO exam. Atreya working in Punjab National Bank cleared SBI PO exam and stays on an odd-numbered floor. There is only one floor between the floors on which Atreya and Mohan stay. Satish stays immediate above the floor on which Yadav stay. Mohan does not stay on the ground floor. Vinoth stays immediate above the floor on which Gowtham stay. There are three floors between the floors on which Harish and Atreya stay. The one who working in Vijaya Bank cleared IBPS PO exam stays immediate above Mohan .Satish stays on the fourth floor. The one who working in IDBI Bank clearedSBI PO exam stays on the third floor.





Study the following carefully and answer the questions given below.
There are eight employees A, B, C, D, E, F, G and H of an organisation working in three departments X, Y and Z. Each of them likes a different colour, viz Black, Brown, Violet, Green, White, Orange, Yellow and Blue, but not necessarily in the same order. There are not more than three employees in any department. 
E likes Brown and does not work in Z department. A does not work in Y department and does not like either Yellow or White. D works in Y department and likes neither Blue nor Yellow B works in X department with only F, who likes Black. H and C do not work in the same department as D. The one who likes Blue works in Y department. The one who likes Orange works in X department. Those who work in Y department like neither White nor Green. C does not like Yellow.




Study the following information carefully and answer the questions. 
A, B, C, D, E, F, G and H are eight members of a family. They belong to three different generations. There are three married couples. All of them are sitting around a circular table, facing the centre but not necessarily in the same order.
· D and F are a married couple. D, the wife of F, sits second to the left of her husband.
· C and A are offspring of D. A is not an immediate neighbour of his mother.
· There is only one person sitting between C and his niece G, but that person is not G’s father.
· E, a bachelor, sits third to the right of his uncle A, but neither to the opposite nor to the immediate left of his father.
· G is not an immediate neighbour of her aunt B. No three females are sitting together.
· C and his sister-in-law are immediate neighbour.






Solution:
1). B) The series is +(13 x 1), + (13 × 2), + (13 x 4),+(13 x 8), +(13 x 16)
ie 7 +13 x 1 = 20, 20 + 13 x2= 46,  46 + 13 x 4 = 98, 98+ 13 × 8 =202,  202 + 13 x 16 = 410, …

2). A) The series is -(1)3,+ (2)3, -(3)3, +(4)3, – (5)3, +(6)3, …
ie 210 - (1)3 = 209, 209 +(2)3 = 217, 217 - (3)3 = 190, 190 + (4)3 = 254, 254 – (5)3 = 129, ….

3). E) The series is +(11 x 1), +(11 × 3),  +(11 x 5), +(11 x 7), +(11 x 9), ...
ie 27 + 11 x 1 = 38, 38 + 11 x 3 = 71, 71 + 11 x 5 = 126, 126 + 11 x 7 = 203, 203 + 11 x 9 = 302, ….

4). D) The given series is -(9 × 9), -(9 x 8), -(9×7), -(9×6), -(9×5), ….
 ie 435 – 9 × 9 = 354, 354 – 9 x 8 = 282, 282 - 9 x 7 = 219, 219 – 9 x 6= 165, 165 - 9 x 5 = 120, …..

5). B) The series is +(14)2, +(13)2, +(12)2, +(11)2, +(10)2, …
ie 4 + 142 = 200, 200 + 132 = 369, 369 + 122 = 513, 513 + 112 = 634, 634 + 102= 734, ….

6). D) The series is 11 x 1 + 12 = 12, 12 x 2 + 22 = 28, 28 x 3 + 32= 93, 93 x 4 + 42 = 388, 388 x 5 + 52 = 1965, ...
There should be 388 in place of 310.

7). A) (3 + 7) x 2 = 20, (20 + 9) x 3 = 87,  (87 + 11) x 4 = 392, (392 + 13) x 5 = 2025, (2025 + 15) x 6 = 12240,
Therefore, there should be 12240 in place of 12246.

8). E) The series is 12 x 0.5 + 0.5 = 6.5, 6.5 x 1 + 1 = 7.5, 7.5 x 1.5 + 1.5 = 12.75, 12.75 x 2 + 2 = 27.5, 27.5 x 2.5 + 2.5 = 71.25, ...
Therefore, there should be 6.5 in place of 6.8.

9). B) The series is 5 x 8 - 7 = 33, 33 x 7 - 6 = 225, 225 x 6 - 5 = 1345, 1345 x 5 - 4 = 6721, 6721 x 4 - 3 = 26881,
Therefore, there should be 6721 in place of 6724.

10). C) The series is (15)2 = 225, (16)2 =256, (17)2 = 289, (18)2 = 324, (19)2 = 361, (20)2  = 400,

Therefore there should be 324 in place of 344.

IBPS PO 2017 DAY 10

   

Directions (Q. 1-5): In each question two equations numbered I and II are given. You have to solve both the equations and mark the answer
a)   If x > y
b)   If x ≥ y
c)   If x < y
d)   If x ≤ y
e)   If x = y or no relation can be established between x and y.

1). I. 4x² – 15x + 14 = 0
II. 6y² – 10y + 4 = 0

2). I. 3x² + 10x + 3 = 0
II. 2y² + 15y + 27 = 0

3). I. 7x² + 12x + 5 = 0
II. 3y² + 7y + 2 = 0

4). I. 16x² – 14x + 3 = 0
II. 6y² – 19y + 15 = 0

5). I. x² + 11x + 18 = 0

II. y² - √81 = 0

Directions (Q. 6-10): In these questions, two equations numbered I and II are given. You have to solve both the equations and mark the appropriate option. Give answer
a)   If x > y
b)   If x ≥ y
c)   If x < y
d)   If x ≤ y
e)   If x = y or relationship between x and y can’t be established

6). I. 32491/2 x - √625 = 4079
II. 57761/2 - √324 = 4162

7). I. 3x – 2y = 37
II. 5x – 3y = 59

8). I. 9x² + 4x – 28 = 0
II. 2y² – 17y + 36 = 0

9). I. √169 x + 561 = 678
II. √324 y + 678 = 822

10). I. 7x² + 19x – 36 = 0
II. 2y² – 21y – 98 = 0

Study the following information carefully and answer the given questions.

Ten persons Shami, Kushak, Nanda, Pranav, Akil, Dileep, Jayanth, Ganapati, Rohan and Vendan are sitting in two rows with five persons in each row. The persons in row one are facing south and the persons in row two are facing north. Each person in row one faces a person from the other row. All of them have a watch of different companies, viz Maxima, Sonata, Matrix, Fossil, Fastrack, Casio, Timex, Citizen, Titan and Espoir, but not necessarily in the same order.

·        The persons who like Fastrack and Casio sit opposite each other.

·        Dileep sits opposite to Shami, who likes Maxima.

·        The one who likes Sonata sits opposite the one who likes Citizen.

·        Vendan is not facing north but sits third to the left of Jayanth, who likes Sonata.

·        There is only one person between Kushak and Nanda.

·        Akil sits at one of the ends of the row and likes Casio.

·        The one who likes Citizen is on the immediate right of Pranav, who does not like Espoir. 

·        The persons who like Matrix and Fossil respectively are not facing north.

·        Nanda likes Timex. The one who likes Fossil sits opposite the one who is second to the right of Kushak.

·        Rohan does not like Espoir. Akil sits opposite the one who sits second to the left of the one who likes Matrix.

Study the following information carefully and answer the given questions.

Ten Friends are sitting in two parallel rows of six seats each. One seat is vacant in each row. Bhavya, Janvi, Hemanika, Preeti and Dharini are sitting in row-1 facing south. Veni, Radha, Charmy, Nisha and Usha are facing north. Each likes a different brand of Soaps i.e. Hamam, Dove, Lux, Liril, Vivel, Pears, Nivea, Mysore Sandal, Medimix and Margo. Nisha sits third to the right of Charmy and likes Liril. Only two people sit between Radha and the vacant seat. Radha does not like Vivel or Lux Soap. Dharini is not an immediate neighbour of Hemanika. Janvi likes Margo. The one who likes Lux Soap faces the one who likes Mysore Sandal. The one who likes Lux sits opposite to the one who sits third right of the person who sits opposite to Nisha. Hemanika is not an immediate neighbour of Preeti. Usha, who likes neither Vivel nor Pears, does not face the vacant seat. Neither Nisha nor Charmy sits at any of the extreme ends of the row. Preeti faces Charmy. Vacant seats are not opposite to each other. Two seats are there between Hemanika and Janvi, who sits third right of the one who likes Nivea. The one who likes Medimix Soap faces the one who likes Liril. The friends who like the Hamam and Mysore Sandal are adjacent to each other. Vacant seat of row – 1 is not an immediate neighbour of Preeti. Radha sits at one of the extreme ends of the row. Charmy does not like Hamam and Mysore Sandal. Vacant seat of row-1 does not face Nisha who doesn’t sit at any of the extreme ends of the row.

Study the following information carefully and answer the given questions.
A number arrangement machine arranges two digit numbers in typical manner. The first step has been obtained by multiplying the digits in input.Multiplication has not been done in any other steps. They are obtained by applying certain logic. Each step is a resultant of previous step.

1.If each middle digit of all the three numbers in the step I are halved and then added, then what will be the final sum?

4

6.5

3.5

7.5

None of these

2.If the final output is subtracted from ‘5’, then what will be the resultant value?

-2.8

-3.2

2.8

3.2

None of these

3.Which of the following combination represent the first digit of the third number and second digit of the first number in step I of the given input?

(5,2)

(8,3)

(3,8)

(2,5)

(2,4)

4. Which of the following represent the difference between the third digit of the third number and second digit of the first number in step I?

4

5

6

-4

None of these

5.What is the multiplication of three numbers obtained in step II?

100

120

240

220

None of these

 ___________Solution with Explanation_________

1). I. 4x2 – 15x + 14 = 0
x = (-8/7), (-7/4)
x = 2, 1.75
II. 6y2 – 10y + 4 = 0
y = (-6/6), (-4/6)
y = 1, 2/3
Hence, x > y
Answer: a)

2). I. 3x2 + 10x + 3 = 0
x = (9/3), (1/3)
x = -3, -1/3
II. 2y2 + 15y + 27 = 0
y = (9/2), (6/2)
y = -4.5, -3
Hence, x ≥ y
Answer: b)

3). I. 7x2 + 12x + 5 = 0
x = (7/7), (5/7)
x = -1, -5/7
II. 3y2 + 7y + 2 = 0
y = (6/3), (1/3)
y = -2, -1/3
Thus relationship can’t be established.
Answer: e)

4). I. 16x2 – 14x + 3 = 0
x = (-8/16), (-6/16)
x = 1/2, 3/8
 II. 6y2 – 19y + 15 = 0
y = (-10/9), (-9/6)
y = 5/3, 3/2
Hence x < y.
Answer: c)

5). I. x2 + 11x + 18 = 0
x = (9/1), (2/1)
x = -9, -2
II. y2 - √81 = 0
y2  = √81
y2 = 9
y = ±3
Hence, no relation can be established.
Answer: e)

6). I. 32491/2 x - √625 = 4079
or, 57x = 4079 + 25 = 4104
x = 4104/57 = 72
II. 57761/2 - √324 = 4162
Or, 76y = 4162 +18 = 4180
y = 4180/76= 55
Hence x > y
Answer: a)

7). 3x – 2y = 37     …(i)
5x – 3y = 59           …(ii)
Equation (i) × 3 – (ii) × 2
(9x -6y = 111) + (10x – 6y = 118)
x = 7
Putting the value of x in eqn (i) we get
21 – 2y = 37
-2y = 36
y = (-16/2) = -8
Hence x > y
Answer: a)

8). I. 9x2 + 4x – 28 = 0
x = (18/9), (-14/9)
x = -2, 14/9
II. 2y2 – 17y + 36 = 0
Y = (-9/2), (-8/2)
Y = 4.5, 4
Hence x < y
Answer: c)

9). I. √169 x + 561 = 678
13x = 678 – 561 = 117
x = 117/13 = 9
II. √324 y + 678 = 822
18y = 822 – 678 = 144
x = 144/8
Hence x > y
Answer: a)

10). I. 7x2 + 19x – 36 = 0
x = (28/7), (-9/7)
x = -4, 9/7
II. 2y2 – 21y – 98 = 0
y = (-28/2), (7/2)
y = 14, -3.5
Hence relationship can’t be established.

Answer: e)

IBPS PO 2017 DAY 9

Study the following information carefully and answer the given questions.
Eight balls are arranged in a stack from bottom to top numbered from 1-8 each from a different e commerce games; Cricket, Football, Hockey, Golf, Tennis, Rugby, Table Tennis and Badminton not necessarily in the same order.Each ball has different colours viz,Red, Blue, Green, Yellow, White, Black, Pink and Orange not necessarily in the same order. The arrangement is based on the following rules:
• The ball from Tennisgame is kept at an even numbered position 
• There are 3 balls between the ball from Tennisgame and the ball with Orangecolour 
• The ball from Golfgame is either at the top or at the bottom of the stack
• Ball number 2 has Redcolour and it is not from Tennisgame
• Ball with the Whitecolour is kept between the ball from Table Tennisgame and the ball having Yellowcolour
• The ball from Cricketgame is kept one ball above the ball from Hockeygame
• There are 4 balls between the ball with Bluecolour and the ball from Table Tennisgame
• There are 3 balls between the ball with Whitecolour and the ball with Greencolour
• The ball from Badmintongame is between the ball with Pinkcolour and the ball from Rugbygame
• The ball from Table Tennisgame does not have Pinkcolour .




Study the following information carefully and answer the given questions.
Seven games - High jump, Pole vault, Long jump, Triple jump, Shot put, Discus throw and Javelin throw–held on Bhubaneswar on Sunday. Each game starting at different times 4 AM, 7 AM, 8 AM, 10 AM, 1 PM, 3 PM and 6 PM not necessarily in the same order. And ends at different times. 
• Long jump is the earliest to start. Its starting time is not after 7 a.m. and its total time is two hours less than the total time of Discus throw. 
• Since High jumpis the least duration game, it starts before 7 p.m. and the games end at 9 p.m. 
• Triple jumpstarts at Sunday 10 a.m. and takes 19 hours to finish the game. 
• There is a four hour gap between the starting times of Shot put, starting at 8 a.m. and Long jump. 
• Shot put takes one hour more than the total time of Long jump to finish the game. 
• High jumpstarts five hours after Pole vaultstarts but takes only three hours to finish the game. 
• Discus throw and Javelin throw take 10 hours and 8 hours to finish the game. 
• Discus throwstarts at 3 p.m. and there is gap of 8 hours between the starting times of Discus throw and Javelin throw. 
• One game ends at 6 p.m. 






Directions (Q. 1-10): In the following questions numbered I and II are given. You have to solve out the equations and Give answer
a)   if x > y
b)   if x ≥ y
c)   if x < y
d)   if x ≤ y
e)   if x = y or the relationship cannot be established

1). I. x² – 1 = 0
II. y² + 4y + 3 = 0

2). I. x² – 7x + 12 = 0
II. y² – 12y + 32 = 0

3). I. x³ – 371 = 629
II. y³ – 543 = 788

4). I. 5x + 2y = 31
II. 3x + 7y = 36

5). I. 2x² + 11x + 12 = 0
II. 5y² + 27y + 10 = 0

6). I. 4x² + 27x + 35 = 0
 II. 3y² - 23y +42 = 0  

7). I. 9x² + 15x - 14 =0
II.7y² – 23y + 16 =0

8). I.x² = 1156
II. y = 3√(35937)

9). I. 2x - 3y = 43
II. 3x + 4y = -12

10). I. 5x² - 44x + 63 = 0
II. 10y² + 23y + 12 = 0







Solution with Answer keys:

1). B)
I. x2 – 1 = 0
x2 = 1
x = ± 1
II. y2 + 4y + 3 = 0
y2 + y + 3y + 3 = 0
y (y + 1) + 3 (y + 1) = 0
(y + 1) (y + 3) = 0
y = -1, -3
hence x ≥ y

2). D) I. x2 -7x + 12 = 0
x2 - 4x – 3x + 12 = 0
x (x - 4) - 3 (x - 4) = 0
(x - 4) (x -3) = 0
 x = 4, 3
II. y2 - 12y + 32 = 0
y2 - 8y - 4y + 32 = 0
y (y-8) – 4 (y- 8) = 0
(y - 8) (y - 4) = 0
y = 8, 4
Hence, x ≤ y

3). C) I. x3 - 371= 629
x3 = 629 + 371
x3 = 1000
x =10
II. y3 - 543 = 788
y3 = 788 + 543
y3 = 1 331
y = 11
Hence, x< y

4). A) I. 5x + 2y =31} x3 …(i)
II. 3x + 7y = 36} x 5 …(ii)
[ (i) – (ii)] we get
- 29y = - 87
y = 3
By putting value of y in I
 5x + 2 x 3 = 31
5x = 25
x = 5
Hence, x> y

5). E) I. 2x2 + 11x + 12 = 0
2x2 + 8x + 3x + 12 = 0
2x(x+4) + 3(x+4) = 0
 (x + 4) (2x + 3) = 0
x = -4, - (3/2)
II.5y2+27y+10=0
5y2 + 25y + 2y + 10 = 0
5y (y + 5) + 2 (y + 5) = 0
(y + 5) (5y + 2) = 0 
y = -5, -(2/5)
Hence, relationship of x and y cannot be established.

6). C)
I. 4x2 + 27x + 35 = 0
x = +(20/4), +(7/4)
x = -5, -(7/4)
II. 3y2 - 23y +42 = 0 
y = -(14/3), -(9/3)
y = (14/3), 3
hence x < y.

7). C)
I. 9x2 + 15x - 14 =0
x = +(21/9), -(6/9)
x = -(7/3), +(2/3)
II.7y2 – 23y + 16 =0
y = -(16/7), -(7/7)
y = (16/7), 1
hence x < y.

8). E) I.x2 = √1156
x = 1156 =  ± 34
II. y = 3√(35937) = 33
Hence no relation can be established.

9). A) 2x - 3y = 43  ..(i)
3x + 4y = -12   …(ii)
Solving equation (i)×3 – (ii) ×2
(6x – 9y = 129) – (6x + 8y = -24) = -17y = 153
Y = -(153/7) = -9
Putting the value of y in equation (i), we get
2x – 3(-9) = 43
Or, 2x + 27 = 43
X = (43-27) / 2 = 16/2 = 8
Hence x > y

10).A)  I. 5x2 - 44x + 63 = 0
x = -(35/5), -(9/5)
x = 7, (9/5)
II. 10y2 + 23y + 12 = 0
y = (15/10), (8/10)
y = -(3/2), -(4/5)


hence x > y.

IBPS PO 2017 DAY 8

         



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Study the following information carefully and answer the given questions.

There are seven workers in a Bank named Elango, Murugan, Ranjith, Milan, Suraj, Albert and Varun. They are born in a different month of the same year from January to July, but not necessarily in the same order. No two people are born in the same month. They also like different national award movies among Ventilator, Pulimurugan, Joker, Dangal, 24, Rustom and Pink.
·        Murugan has his birthday in a month which has 30 days.
·        The ones who have their birthday in the month immediately preceding & succeeding that of Murugan's like 24 and Rustom respectively
·        Ranjith has his birthday in the month just before that of Murugan.
·        Albert has his birthday in a month that has more than 30 days.
·        Joker is not liked by Albert or Milan.
·        Suraj likes Pulimurugan. There is only one person's birthday between Suraj and the one who likes Ventilator.
·        The persons who like Dangal or Pink do not have birthdays in successive months. Murugan does not like Dangal or Pink.
·        There are three persons' birthday between Elango and the one who likes Joker. Elango is not born in February.
·        The one who likes Pink has his birthday before the one who likes Dangal.









Study the following information carefully and answer the given questions.


There are seven persons Gopesh, Charan, Dhikshit, Piyush, Kalyan, Ahmad and Lakshman who participated in a quiz competition which started on Monday and ended on Sunday. In the first round of the competition, each of them played quiz under different subjects Reasoning, Aptitude, English, Computer, Marketing, General Knowledge and Current Affairs, but not necessarily in the same order. They like different Countries, Brazil, Argentina, Germany, Sweden, Poland, Russia and Moscow, but not necessarily in the same order.
Charan did not play on the day either immediately before or immediately after the quiz of Piyush, who does not like either Poland or Brazil or Sweden Country. Two quizzes were held between the quiz of Lakshman and Ahmad, neither of whom played on Monday. There was one quiz between the quiz of Piyush and Dhikshit. But Dhikshit’s quiz did not happen either on Monday or on Wednesday. Dhikshit likes Argentina Country and played Reasoning. The one, who played under English subject on the last day of competition, likes Germany Country. Kalyan played immediately after Dhikshit and he likes Brazil Country. Gopesh does not like Poland Country and played under Computer subject. Piyush did not play for either Current Affairs or General Knowledge ream. The one who played for Marketing subject was scheduled immediately after the quiz of Reasoning subject. Lakshman, who likes Russia, played on the fourth day of the competition but played neither Reasoning subject nor Aptitude subject.






1). The ratio of the radii of two right circular cylinders (A and B) is 2 : 5. The ratio of the highest of cylinders A to B is 3 : 1. What is the ratio of the volumes of cylinders A to B?
a)   12:25
b)   9:25
c)   9:20
d)   3:5
e)   12:35

2). Raja gives 30% of his salary to his mother, 40% of the remaining salary he invests in an insurance scheme and PPF in the ratio of 4 : 3 and the remaining he keeps in his bank account. If the difference between the amount he gives to his mother and that he invests in insurance scheme is Rs.8400, how much is Raja's salary?
a)   Rs.60,000
b)   Rs.62,000
c)   Rs.64,000
d)   Rs.65,000
e)   Rs.54,000

3). C is 40% less efficient than A. A and B together can finish a piece of work in 10 days. B and C together can do it in 15 days. In how many days can A alone finish the same piece of work?
a)   18
b)   12
c)   14
d)   20
e)   15

4). In a bag there are 7 red balls and 5 green balls. Three balls are picked at random. What is the probability that two balls are red and one ball is green in colour?
a)   29/44
b)   21/44
c)   27/44
d)   23/44
e)   19/44

5). Shyama invested Rs. P for 2 years in scheme A, which offered 11% pa simple interest. She also invested Rs. 600+P in scheme B, which offered 20% compound interest (compound annually)for 2 years. If the amount received from scheme A was less than that received from scheme B by Rs. 1216 then what is the value of P?
a)   Rs. 1500
b)   Rs. 1400
c)   Rs. 2000
d)   Rs. 1600
e)   Rs. 1800

Directions (Q. 6-10): What approximate value will come in place of question mark (?) in the given questions? (You are not expected to calculate the exact value.)
6). 619.002 - 134.99 ÷ 14.998—(9.01)2=?
a)   720
b)   530
c)   650
d)   690
e)   490

7). 439.97 ÷ 15 .02 + 208.08 ÷ 8.01 — 16.01 =?
a)   120
b)   60
c)   100
d)   80
e)   40

8). 4? × √226 =245.998 ÷ 8.001 + 929.99
a)   4
b)   5
c)   2
d)   3
e)   1

9). ?%of(140.06 x 7.99 — 679.92) = 330.01
a)   70
b)   90
c)   80
d)   50
e)   None of these

10). 40% of 859 + 86.01 ÷ 7.99 = ?
a)   398
b)   286
c)   412
d)   215
e)   355







Explanation With Answer Key

1). A) Let the radius of cylinder A be 2x and that of cylinder B be 5x.
Now, height of cylinder A = 3y and height of cylinder B = y
Now, volume of cylinder A = ￗr2h
= (22/7)x (2x)2 x 3y = (22/7) x 4x2 x 3y
= (22/7) x l2 x2y
Volume of cylinder B = ￗr2h
=( 22/7)×(5x)2 × y =  (22/7) x 25 x2y
Reqd ratio = [ (22/7) x l2 x2y] / [(22/7) x 25 x2y] = 12/25
= 12:25

2). A) Let Raja's salary be Rs. x.
Raja gives 30% of his salary to his mother.
Raja gives[(x × 30)/100 = Rs. 3x/10] to his mother
Remaining salary of Raja = x – (3x /10) = Rs. 7x /10
Investments of Raja in insurance and PPF is 40% of the remaining salary.
Insurance + PPF = (7x x 40)/ (10x100) = 7x/25
Remaining salary of Raja = 7x/10 – 7x/25
= (35x —14x)/50 = 21x /50
Raja's investment in insurance scheme
= (7x/25) × (4/7) = 4x/25
Now, according to the question,
3x/10 - 4x/7 = 8400
or, (15x-8x) / 50 =8400
or,  7x = 8400 x 50
x = (8400x 50)/7 =1200 x 50 = Rs. 60000

3). B) Suppose total work = 60 units (LCM of 10 and 15)
(A + B)'s one day's work = 60/10
= 6 units
And (B + C)'s one day's work = 60/15 = 4 unit
According to the question, C : A = 60 : 100
or, C :A = 3 : 5
C/A = 3/5
Or, A = 5C/3
Again, A +B = 6units  ..(i)
B+C = 4 units   …(ii)
Putting the value of A in equation (i), we get
[ 5C/3 + B = 6 unit ] – [B + C = 4 units]
= 5C/3 - C=2units
Or, 2C/3 = 2 units
 C = 3 units
Then A = 5C/3 = 5×3 / 5 = 5 units
Now, total work is 60 units Then A alone can do the work in
(60 / 5 =) 12 days

4). B) Total number of balls = 7 + 5 = 12
Now, three halls are picked randomly
Then, the number of sample space n(S)
= 12C3 =(10 ×11 ×12) / (1×2×3) = 220
The number of events
n(E) = 7C2 x5C1 = [(6x7)/2] x 5
= 21 x 5 = 105
105 21 P(E) = n(E)/n(S)=105/220 = 21/24

5). D) Amount received from scheme A
= P+ [(Px2x11)/100] =( 100P+22P)/100 = 122P/100
Amount received from scheme B
= (P + 600) [1+ (20/100)]2
= (P + 600) (6/5)2
= (P + 600) (36/25)
= 36P/25 + (600x36)/25 = 36P/25 + 864
 Now, according to the question,
36P/25 + 864 – 122P/100 = 1216
Or, 36P/25 – 122P/100 = 1216-864
Or, (144P-122P)/100 = 352
Or, 22P = 352×100
P = (352×100) / 22 = Rs. 1600

6). B) ? = 619.002 – 134.99 ÷ 14.998 –(9.01) = 620 – 135 ÷ 15 – (9)2
= 620 – 90 = 530

7). E) ? = 439.97 ÷ 15.02 + 208.08 ÷ 8.01 –16.01 = 450 ÷ 15 + 208 ÷ 8 – 16
= 30 + 26 – 16 =30 + 10 = 40

8). D) 4? x √226 = 245.998 ÷ 8.001 + 929.99
or, 4? x √225 = 248 ÷ 8 + 930
or, 4? x 15 = 31 + 930 = 961
or 4? = 960/15 = 64 = 43
? = 3

9). E) ?% of (140.06 x 7.99 — 679.92) = 330.01
= [?x(140x8-680)] / 100 = 330
or, ? x (1120 — 680) = 330 x 100
or, ? x 440 = 33000
? = 33000 / 440 = 75

10). E) ? 40% of 859 + 86.01 ÷ 7.99
= (40 x 860) / 100  + 86 ÷ 8

= 344 + 11 = 355

IBPS PO 2017 DAY 7

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Study the following information carefully and answer the given questions.

There are seven national parks namely Jim Corbett, Ranthambore, Kaziranga, Periyar, Bandipur, Manas and Satpura located in different cities such as Chennai, Mumbai, Kochi, Hyderabad, Bangalore, Patna & Kolkata, not necessarily in the same order. Different animals such as, Lion, Tiger, Elephant and Deer were presented in the park. Depends on the length of the Parks it was listed from 1 to 7 positions, from top to bottom. The following information is known about them.
·        Not more than 3 Parks has same animals.
·        There's only one park has Deer which belongs to Bangalore and listed in bottom 3 positions and is not Kaziranga Park
·        The one belongs to Chennai listed just ahead of Ranthambore Park, which does not belong to Bangalore.
·        The park in which Tiger presented is listed 1st.
·        The Parks which listed in 3rd and 4th have same animals and it is not Lion.
·        The park located in Mumbai listed in last and park located in Patna listed as 4th and none of them are has Tiger.
·        Manas Park have Lion animal and is not in bottom 3.
·        Periyar Park belongs to Hyderabad and Satpura Park belongs to Chennai, both are not having lion animal and in the list there are two Parks between them.
·        The Parks from Kolkata and Mumbai are having same animals.
·        Bandipur Park not located in Kochi, Mumbai or Bangalore.








Study the following information carefully and answer the given questions.

Six friends - Harish, Mohan, Suresh, Vikram, Ram, and Gopal went to six different cities namely Mumbai, Bangalore, Hyderabad, Delhi, Chennai and Patna (not necessarily in the same order) to attend different probationary officers exam. They exams are IBPS PO, SBI PO, BOB PO, Syndicate Bank PO, Indian Bank PO and Dena Bank PO. They attend exams from Monday to Saturday (not necessarily in the same order).
·        Harish attends exam in Delhi and he wrote either IBPS PO or Dena Bank PO.
·        Ram did not wrote Dena Bank PO exam
·        Suresh attends exam on Tuesday and he is not wrote IBPS PO or BOB PO exam.
·        The person who wrote the Syndicate Bank PO exam wrote on Saturday and neither in Mumbai nor in Bangalore.
·        Gopal wrote the SBI PO exam in Patna but not on Wednesday.
·        Ram attends the exam at Hyderabad and wrote the exam one day before Gopal
·        On first day of the week, Mohan attends the exam in Bangalore.
·        The person who attends the exam on Thursday is not wrote BOB PO or IBPS PO exam.
·        The person who attends the exam on Thursday is not Gopal.




Directions (Q. 1-5): In each of the questions below there are given four conclusions followed by five statements numbered I, II, III, IV & IV. You have to take the given statements to be true even if they seem to be at variance with commonly known facts. Read all the statements and then decide which of the given statement logically follows from the given conclusion disregarding commonly known facts.

1). Conclusions:
Some cups are balls
Some pins are car is a possibility
Some rings are balls
Some balls are pins is a possibility
a)  Statements:
Some balls are cars
Some cars are rings
All rings are cups
Some cups are pins
b)  Statements:
Some cars are balls
All cars are rings
All rings are cups
Some cups are pins
c)  Statements:
All balls are cars
Some cars are rings
All rings are cups
Some cups are pins
d)  Statements:
Some balls are cars
All cars are rings
All rings are cups
No cup is a pin
e)  Statements:
All balls are cars
All cars are rings
All rings are cups
No cup is a pin
a)   Only I follows  
b)   Only II follows
c)   Only II & III follows
d)   Only IV follows
e)   Only V follows

2). Conclusions:
Some pencils are tables
All chairs are boxes
Some boxes are desk
All desks are pencils
a)  Statements:
Some desks are chairs
All chairs are tables
All tables are boxes
Some boxes are pencils
b)   Statements:
Some desks are chairs
No chair is table
All tables are boxes
All boxes are pencils
c)  Statements:
All desks are chairs
All chairs are tables
All tables are boxes
All boxes are pencils
d)  Statements:
All desks are chairs
All chairs are tables
No table is box
Some boxes are pencils
e)  Statements:
All desks are chairs
All chairs are tables
All tables are boxes
No box is pencil
a)   Only I follows  
b)   Only I & II follows
c)   Only III follows
d)   Only IV follows
e)   Only V follows

3). Conclusions:
Some rivers are not roads
Some jungles may be roads
Some cars are roads
Some rivers are trees
a)  Statements:
All roads are cars
No car is tree
All trees are jungles
All jungles are rivers
b)  Statements:
All roads are cars
Some cars are trees
All trees are jungles
Some jungles are not rivers
c)  Statements:
All roads are cars
No car is tree
Some trees are not jungles
All jungles are rivers
d)  Statements:
Some roads are cars
No car is tree
Some trees are not jungles
Some jungles are rivers
e)  Statements:
All roads are cars
No car is tree
Some trees are jungles
All jungles are rivers
a)   Only I follows  
b)   Only II follows
c)   Only II & III follows
d)   Only IV follows
e)   Only V follows


4). Conclusions:
Some pens are pins is a possibility
Some pencils are pads
Some papers are pads is a possibility
Some papers are pens
a)  Statements:
Some pens are papers
Some pencils are papers
Some pads are pencils
Some pins are pads
b)  Statements:
Some pens are papers
Some pencils are papers
No pad is a pencil
Some pins are pads
c)  Statements:
All pens are papers
Some pencils are papers
All pads are pencils
Some pins are pads
d)  Statements:
Some pens are papers
All papers are pencils
Some pads are not pencils
Some pins are pads
e)  Statements:
No pen is a paper
All papers are pencils
Some pads are pencil
Some pins are pads
a)   Only I follows  
b)   Only II follows
c)   Only II & III follows
d)   Only I & III follows
e)   Only IV & V follows

5). Conclusions:
All papers are cups
Some plates are cup is a possibility
Some cups are jugs
Some bottles are papers
a)  Statements:
All papers are bottles
Some bottles are cups
Some cups are jugs
Some jugs are plates
b)  Statements:
All papers are bottles
All bottles are cups
Some cups are jugs
Some jugs are plates
c)  Statements:
Some papers are bottles
Some bottles are cups
Some cups are jugs
Some jugs are plates
d)  Statements:
All papers are bottles
All bottles are cups
Some cups are not jugs
Some jugs are plates
e)  Statements:
Some papers are bottles
All bottles are cups
Some cups are jugs
Some jugs are plates
a)   Only I follows  
b)   Only II follows
c)   Only II & IV follows
d)   Only I & III follows
e)   Only V follows

PROFIT AND LOSS: PART-2

Type 6:

1). An article was purchased for Rs. 78,350/-. Its price was marked up by 30%. It was sold at a discount of 20% on the marked up price. What was the profit percent on the cost price?

Solution:

Cost Price = Rs.78350

Marked Price = 78350 x 130/100 = Rs.101855

Selling Price = 101855 x 80/100 = Rs.81484

Profit = 81484 – 78350 = 3134

Therefore Profit% = 3134/78350 x 100 = 4%

Type 7:

2). A shopkeeper purchases 12 balloons for Rs.10 and sells them at 10 balloons for Rs.12.Thus, he earns a profit of

Solution:

Number of Balloons purchased and sold be = LCM (12,10) = 60

CP = 60/12 x 10 = 50; SP = 60/10 x 12 = 72

Profit = (72 – 50)/50 x 100 = 22/50 x 100 = 44%

Type 8:

3). The cost price of an article is Rs. 800. After allowing a discount of 10%, a gain of 12.5% was made. Then the marked price of the article is

Solution:

CP = Rs 800

Gain% = 12.5%

SP = 800 + 12.5% of 800 = 800 + 25/200 x 800 = 800 + 100 = Rs 900

MP = SP + Discount

MP = 900 + 10% of MP

MP – MP/10 = 900

9MP/10 = 900

MP = (900 x 10)/9 = Rs 1000

Type 9:

4). If the selling price of an article is doubled, then its loss per cent is converted into equal profit per cent. The loss per cent on the article is

Solution:

Let CP = C, SP = S, Loss% = x %

=> x = (C – S)/C x 100 --------------(1)

When SP is doubled, loss% becomes profit%.

x = (2S – C)/C x 100 --------------(2)

From eqns (1) and (2)

2S – C = C – S

3S = 2C => S = 2/3 C

Substituting b = 2/3 a in eqn (1)

x = (C – 2/3 C)/C x 100= (C/3)/C x 100  = 100/3 = 33 1/3%

Type 10:

5). A man bought an article listed at Rs. 1500 with a discount of 20% offered on the list price. What additional discount must be offered to man to bring the net price to Rs. 1,104?

Solution:

SP of the article = MP – Discount = 1500 – 20% of 1500 = 1500 – 300 = Rs 1200

Therefore, additional discount = (1200 – 1104)/1200 x 100 = (96/1200) x 100 = 8%

Exercise Questions:

1). Giri purchased 100 shirts at Rs. 450 per piece. While selling he offered 10%discount on the labeled price and earned a profit of 20%. What was the labeled price of each shirt?

a)   Rs. 540

b)   Rs. 650

c)   Rs. 590

d)   Rs. 600

e)   None of these

2). If the cost price of 15 Pencils is equal to the selling price of 12 pencils, find gain percent.

a)   20

b)   25

c)   18

d)   21

e)   None of these

3). A dealer purchased a printing machine for Rs. 7660. He allows a discount of 12% on its marked price and still gains 10%. Find the marked price of the machine. 

a)   9575

b)   8765

c)   10985

d)   8995

e)   None of these

4). A fruit seller buys oranges at 2 for a rupee and sells them at 5 for three rupees. His gain percent is

a)   10%

b)   15%

c)   20%

d)   25%

e)   30%

5). The labeled price of a Juicer is Rs.620. If it is sold at 15% discount and the dealers earn a 20% profit, what is the cost price?

a)   Rs.439.16

b)   Rs.423.16

c)   Rs.412.16        

d)   Rs.436.11

e)   None of these

6). A person sold an toy for Rs. 136 and got 15% loss, had he sold it for Rs. N, he would have got a profit of 15%. Which one of the following is correct?

a)   190 < N < 200

b)   180 < N < 190

c)   170 < N < 180

d)   160 < N < 170

e)   None of these

7). A person bought an old Bike at Rs.7200 and spent 15% of it on repairing. If he wants to make a profit of Rs.648 then what percentage should be added to purchase price?

a)   15%       

b)   20%

c)   24%

d)   25%

e)   None of these

8). A shopkeeper gave an additional 40% discount on the reduced price after giving 25% standard concession on that item, if a person bought that item for Rs.1260, what is the original price of the item?

a)   Rs.2400

b)   Rs.2800

c)   Rs.3200

d)   Rs.2000

e)   None of these

9). 20 mangoes were bought for a rupee. Approximately how many mangoes must be sold for a rupee to gain a profit of 30%?

a)   12

b)   10

c)   15

d)   20

e)   25

10). A seller wants to earn 12% profit on an item after giving 20% discount to the customer. By what percentage should he increase his marked price to arrive at the label price?

a)   24%

b)   32%

c)   42%

d)   16%

e)   None of these

_____________________________________________

Answers with Explanation: Reasoning

Directions (Q. 1-5): Syllogism

1). B)

2). C)

3). A)

4). D)

5). D)

Answers with Explanation: MATH

1). Answer: d)

Let the labeled price of each shirt be Rs. x.

According to the question,

90% of x = 120 × 450 / 100

90 / 100 × x = 120 × 450 / 100

x = 120 × 450 / 90

x = Rs. 600

2). Answer: b)

Gain percent = (15 – 12) / 12 × 100 = 25%

3). Answer: a)

Cost price of the machine = Rs. 7660, Gain% = 10%.
Therefore, selling price = [{(100 + gain%)/100} × CP]
                                     = Rs. [{(100 + 10)/100} × 7660]
                                     = Rs. [(110/100) × 7660]
                                     = Rs. 8426.
Let the marked price be Rs. x.
Then, the discount = 12% of x
                               = {x × (12/100)}
                               = 3x/25
Therefore, SP = (Marked Price) - (discount)
                       = (x - 3x/25)
                       = 22x/25.
But, the SP = Rs. 8426.
Therefore, 22x/25 = 8426
⇒ x = (8426 × 25/22)
⇒ x = 9575.
Hence, the marked price of the Printing machine is Rs. 9575. 

4). Answer: c)

The cost price of 1 lemon =Rs.0 .50
Selling price of 1 lemon = Rs.0.60;  

Therefore,  profit = Rs.0.10
:.  Gain per cent = 0.10 × 100/0.50 = 20%.

5). Answer: a)

The selling price = Rs.620 – 15% of 620 = 620 – 93 = Rs.527

Rs.527 is 120% of the cost price;

Therefore, cost price = 527 × 100/120 = Rs.439.16.

6). Answer: b)

Cost price = (selling price x 100)/(100 - loss%)
= (136 x 100)/(100 - 15)
= (136 x 100)/85
= Rs. 160
Selling price (N) = 160 x (100 + 15)/100 = (160 x 115)/100
= Rs. 184
∴ Option (b) is correct because [180 < N < 190].

7). Answer: c)

CP = Rs.7200
CP + repair cost + profit expected = Rs.7200 + 1080 +648 = Rs.8928.
The amount to be added to CP = Rs.8928 – Rs.7200 = Rs.1728
The percentage of amount to be added to CP = 1728 x 100/7200 = 24%

8). Answer: b)

Let the original price be ‘x’

The price after 1st concession of 25% = x – 25x/100 = x – x/4 = 3x/4

The Price after additional discount 40% = 3x/4 – 3x/4 X 40/100 = 30x – 12x/40

= 9x/20, i.e. 9x/20 = Rs.1260,

:. x = 1260 x 20 /9 = Rs.2800.

9). Answer: c)

Given 20 mangoes cost 100 paisa.

:. 1 mango’s cost = 5 paisa.

For a getting a profit of 30% , the SP per mango should be equal to 6.5 paise.

:. For 1 Rupee, the No. of mangoes to be sold = 100/6.5

= 15 nos. approximately.

10). Answer: e)

Let x = marked price and the CP be Rs.100.

Initial SP = Rs.112.

To give 20% discount = x – 20x/100 = Rs.112.

= x – x/5 = Rs.112,  4x = 112 x 5

x = Rs.140.

Here marked profit = Rs.40.

Percent profit 40%